In this article, you will learn about the Python function arguments and how they are used in Python functions. You will learn in detail about different types of Python function arguments.
Introduction |
Types of arguments in Python functions |
Python Default Arguments |
Python Keyword Arguments |
Python Variable-length Arguments |
The first thing a programmer must be aware of is that parameters and arguments are clearly two different things although people use them synonymously.
Parameters are the variables that are defined or used inside parentheses while defining a function, whereas arguments are the value passed for these parameters while calling a function. Arguments are the values that are passed to the function at run-time so that the function can do the designated task using these values.
Now that you know about Python function arguments and parameters, let’s have a look at a simple program to highlight more before discussing the types of arguments that can be passed to a function.
#Defining a function first to return the value of parameter
def display(x): #x is the parameter
return x
#Calling the function and supplying arguments
print ("Hello " + display('David')) #'David' is the argument
In this example, we have defined a function with parameter ‘x’. Basically, this function will return whatever the value is passed as an argument while calling.
Output
Hello David
There are three types of Python function arguments using which we can call a function.
Sometimes we may want to use parameters in a function that takes default values in case the user doesn’t want to provide a value for them.
For this, we can use default arguments which assumes a default value if a value is not supplied as an argument while calling the function. In parameters list, we can give default values to one or more parameters.
An assignment operator ‘=’ is used to give a default value to an argument. Here is an example.
def sum(a=4, b=2): #2 is supplied as default argument
""" This function will print sum of two numbers
if the arguments are not supplied
it will add the default value """
print (a+b)
sum(1,2) #calling with arguments
sum( ) #calling without arguments
Output
3 6
In the program above, default arguments 2 and 4 are supplied to the function. First, the user has provided the arguments 1 and 2, hence the function prints their sum which is 3. In the second call, the user has not provided the arguments. Thus the function takes the default arguments and prints their sum.
SyntaxError
.
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Why does Python throw error while using default argument before non-default argument?
Well, the reason is simple.
In function, the values are assigned to parameters in order, by their position. The value of default argument may be optional as there is the default value if not provided, but the value for a non-default argument is mandatory as there exists no default value for this.
For example, def func(a=1, b)
is not allowed because when we will call the function using func(5)
, the default argument a
will be replaced by 5, leaving no value for parameter b
. That is why a non-default argument is always placed before default argument.
In function, the values passed through arguments are assigned to parameters in order, by their position.
With Keyword arguments, we can use the name of the parameter irrespective of its position while calling the function to supply the values. All the keyword arguments must match one of the arguments accepted by the function.
Here is an example.
def print_name(name1, name2):
""" This function prints the name """
print (name1 + " and " + name2 + " are friends")
#calling the function
print_name(name2 = 'John',name1 = 'Gary')
Output
Gary and John are friends
Notice in above example, if we had supplied arguments as print_name('John','Gary')
, the output would have been John and Gary are friends
as the values would have been assigned by arguments position.
But using keyword arguments by specifying the name of the argument itself, we don’t have to worry about their position. This makes using function easier as we don’t need to worry about the order of arguments.
Sometimes you may need more arguments to process function then you mentioned in the definition. If we don’t know in advance about the arguments needed in function, we can use variable-length arguments also called arbitrary arguments.
For this an asterisk (*) is placed before a parameter in function definition which can hold non-keyworded variable-length arguments and a double asterisk (**) is placed before a parameter in function which can hold keyworded variable-length arguments.
If we use one asterisk (*) like *var, then all the positional arguments from that point till the end are collected as a tuple called ‘var’ and if we use two asterisks (**) before a variable like **var, then all the positional arguments from that point till the end are collected as a dictionary called ‘var’.
Here is an example.
def display(*name, **address):
for items in name:
print (items)
for items in address.items():
print (items)
#Calling the function
display('john','Mary','Nina',John='LA',Mary='NY',Nina='DC')
Output
John
Mary
Nina
('John', 'LA')
('Mary', 'NY')
('Nina', 'DC')
As you can see in the example above, *name
takes all the non-keyworded arguments John
, Mary
, and Nina
wrapped into a tuple, whereas **address
takes all the keyworded arguments John='LA'
, Mary ='NY'
, and Nina='DC'
wrapped into a dictionary.
In this particular example, the function took three arbitrary variables using one variable with either asterisk(*) or double asterisk(**), but using variable length arguments we can take any number of arbitrary arguments.